{"id":516,"date":"2004-01-26T18:00:00","date_gmt":"2004-01-26T18:00:00","guid":{"rendered":"http:\/\/markwilson.me.uk\/blog\/2004\/01\/determining-costs-for-active-directory.htm"},"modified":"2007-07-24T19:36:35","modified_gmt":"2007-07-24T18:36:35","slug":"determining-costs-for-active-directory","status":"publish","type":"post","link":"https:\/\/www.markwilson.co.uk\/blog\/2004\/01\/determining-costs-for-active-directory.htm","title":{"rendered":"Determining costs for Active Directory site links"},"content":{"rendered":"<p><!--110916837894441986-->Whilst reviewing a colleague&#8217;s Active Directory design document today, I came across the following model for determining the cost of a site link, depending on the available bandwidth:<\/p>\n<p>Replication cost = 1024 x 1\/<sub>log<\/sub>bandwidth (in Kbps)<\/p>\n<p>The following table gives some example costs for common bandwidth values:<\/p>\n<table>\n<thead>\n<th>Bandwidth (Kbps)<\/th>\n<th>Replication cost<\/th>\n<\/thead>\n<tbody>\n<tr class=\"even\">\n<td>28<\/td>\n<td>702<\/td>\n<\/tr>\n<tr class=\"odd\">\n<td>56<\/td>\n<td>586<\/td>\n<\/tr>\n<tr class=\"even\">\n<td>64<\/td>\n<td>567<\/td>\n<\/tr>\n<tr class=\"odd\">\n<td>96<\/td>\n<td>517<\/td>\n<\/tr>\n<tr class=\"even\">\n<td>128<\/td>\n<td>486<\/td>\n<\/tr>\n<tr class=\"odd\">\n<td>256<\/td>\n<td>425<\/td>\n<\/tr>\n<tr class=\"even\">\n<td>512<\/td>\n<td>378<\/td>\n<\/tr>\n<tr class=\"odd\">\n<td>1024<\/td>\n<td>340<\/td>\n<\/tr>\n<tr class=\"even\">\n<td>2048<\/td>\n<td>309<\/td>\n<\/tr>\n<tr class=\"odd\">\n<td>4096<\/td>\n<td>283<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"<p>Whilst reviewing a colleague&#8217;s Active Directory design document today, I came across the following model for determining the cost of a site link, depending on the available bandwidth: Replication cost = 1024 x 1\/logbandwidth (in Kbps) The following table gives some example costs for common bandwidth values: Bandwidth (Kbps) Replication cost 28 702 56 586 &hellip; <a href=\"https:\/\/www.markwilson.co.uk\/blog\/2004\/01\/determining-costs-for-active-directory.htm\" class=\"more-link\">Continue reading <span class=\"screen-reader-text\">Determining costs for Active Directory site links<\/span><\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_exactmetrics_skip_tracking":false,"_exactmetrics_sitenote_active":false,"_exactmetrics_sitenote_note":"","_exactmetrics_sitenote_category":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[],"tags":[102],"class_list":["post-516","post","type-post","status-publish","format-standard","hentry","tag-active-directory"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.5 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Determining costs for Active Directory site links - markwilson.it<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.markwilson.co.uk\/blog\/2004\/01\/determining-costs-for-active-directory.htm\" \/>\n<meta property=\"og:locale\" content=\"en_GB\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Determining costs for Active Directory site links - markwilson.it\" \/>\n<meta property=\"og:description\" content=\"Whilst reviewing a colleague&#8217;s Active Directory design document today, I came across the following model for determining the cost of a site link, depending on the available bandwidth: Replication cost = 1024 x 1\/logbandwidth (in Kbps) The following table gives some example costs for common bandwidth values: Bandwidth (Kbps) Replication cost 28 702 56 586 &hellip; 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Domain controller (DC) placement can have a huge impact\u2026","rel":"","context":"In \"Microsoft Active Directory\"","block_context":{"text":"Microsoft Active Directory","link":"https:\/\/www.markwilson.co.uk\/blog\/tag\/active-directory"},"img":{"alt_text":"","src":"","width":0,"height":0},"classes":[]},{"id":709,"url":"https:\/\/www.markwilson.co.uk\/blog\/2006\/04\/maximising-active-directory-performance.htm","url_meta":{"origin":516,"position":1},"title":"Maximising Active Directory performance and replication troubleshooting","author":"Mark Wilson","date":"Tuesday 11 April 2006","format":false,"excerpt":"Whenever I see that John Craddock and Sally Storey (from Kimberry Associates) are presenting a new seminar on behalf of Microsoft I try to attend. Not just because the content is well presented but because of the relevance of the material, some of which would involve wading through reams of\u2026","rel":"","context":"In \"Microsoft Active Directory\"","block_context":{"text":"Microsoft Active Directory","link":"https:\/\/www.markwilson.co.uk\/blog\/tag\/active-directory"},"img":{"alt_text":"","src":"http:\/\/www.assoc-amazon.co.uk\/e\/ir?t=marsweblo-21&l=ur2&o=2","width":350,"height":200},"classes":[]},{"id":1204,"url":"https:\/\/www.markwilson.co.uk\/blog\/2008\/09\/active-directory-design-considerations-part-2-forest-and-domain-design.htm","url_meta":{"origin":516,"position":2},"title":"Active Directory design considerations: part 2 (forest and domain design)","author":"Mark Wilson","date":"Tuesday 16 September 2008","format":false,"excerpt":"Having set the scene for this series of posts, the first area to examine is Active Directory forest and domain design. 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